← Back to the archiveSHORT / 065
How One Line Blooms an 8-Petal Lotus
Waves & probability

How One Line Blooms an 8-Petal Lotus

BEHIND THE WORK

How does a single continuous line bloom into an eight-petal lotus?

Governed by an 8:3 resonant epitrochoid where x(t) = 0.22 (11 cos t − 2.4 cos 11t/3) and y(t) = 0.22 (11 sin t − 2.4 sin 11t/3) over 0 ≤ t ≤ 6π, a single rolling point traces eight outer blossom petals while cross-threading through the core to weave an intricate inner rosette. Pure mathematical harmony creates sacred botanical geometry.

Artismathic turns equations into visual art—one function at a time.

Music: 'Eternal Garden' by Dan Henig

#MathArt #SacredGeometry #Geometry #Mandala #DigitalArt

THE MATHEMATICAL RULE

x(t)=0.22(11cost−2.4cos11t/3)x(t) = 0.22 (11 cos t − 2.4 cos 11t/3)y(t)=0.22(11sint−2.4sin11t/3)y(t) = 0.22 (11 sin t − 2.4 sin 11t/3)0≤t≤6π0 ≤ t ≤ 6π
Watch the drawing↗

WATCH IT COME TO LIFE

Watch the drawing

YouTube loads only after you press play.